Mechanics RRB PYQ – Physics Previous Year Questions
Practice Mechanics RRB PYQ questions from Railway examinations, including RRB NTPC PYQ, RRB Group D PYQ, RRB JE PYQ, RRB ALP PYQ and RRB Technician PYQ. This topic-wise Physics question set covers important concepts related to work, power, energy, mass, force, Newton’s laws of motion, momentum, distance, displacement, speed, velocity, acceleration, equations of motion, friction and motion, helping you revise essential Physics concepts for RRB examinations.
Each question includes the correct answer and an explanation to help you understand the concept, strengthen your Physics fundamentals, and revise important Mechanics topics for RRB Railway examinations.
Start practicing Mechanics RRB PYQs and strengthen your Physics preparation.
671
A 100 g cricket ball moving at 30 m/s is stopped by a player in 0.05 s. What is the average force exerted by the player?
RRB Group D
23/10/2018 / Shift-II
2018
✓ Answer:C−60 N
Taking the initial direction as positive, F = 0.1(0 − 30)/0.05 = −60 N.
672
Which is an example of pulling?
RRB Group D
27/11/2018 / Shift-III
2018
✓ Answer:AHoisting a flag
Hoisting a flag involves pulling the rope downward to raise the flag.
673
A 2 kg object accelerates at 4 m/s². What net force acts on it?
RRB Group D
22/09/2018 / Shift-II
2018
✓ Answer:D8.0 N
F = ma = 2 × 4 = 8 N.
674
All forces have ______.
RRB Group D
27/11/2018 / Shift-I
2018
✓ Answer:ABoth magnitude and direction
Force is a vector quantity, so it has both magnitude and direction.
675
The speed of a 100 kg body increases uniformly from 5 m/s to 15 m/s in 5 s. Find the force.
RRB Group D
01/10/2018 / Shift-II
2018
✓ Answer:D200 N
F = 100(15 − 5)/5 = 200 N.
676
A 1000 kg car travelling at 72 km/h stops in 4 s after braking. Find the magnitude of the braking force.
RRB Group D
27/11/2018 / Shift-I
2018
✓ Answer:D5.0 × 10³ N
72 km/h = 20 m/s. The deceleration magnitude is 20/4 = 5 m/s², so F = 1000 × 5 = 5000 N.
677
A 20 kg object accelerates at 4 m/s². Find the applied force.
RRB Group D
26/10/2018 / Shift-II
2018
✓ Answer:A80 N
F = ma = 20 × 4 = 80 N.
678
A force of 20 N gives an object an acceleration of 2 m/s². Find its mass.
RRB Group D
28/11/2018 / Shift-I
2018
✓ Answer:D10 kg
m = F/a = 20/2 = 10 kg.
679
Calculate the acceleration when a force of 100 N acts on a 50 kg object.
RRB Group D
10/12/2018 / Shift-I
2018
✓ Answer:A2 m/s²
a = F/m = 100/50 = 2 m/s².
680
Two equal forces act on a body in opposite directions. What is their resultant?
RRB Group D; RRB Group D
16/10/2018 / Shift-III; 28/09/2018 / Shift-II
2018
✓ Answer:DZero
Equal opposite forces cancel, giving zero resultant force.
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