Q

In a normal eye, the distance of the retina from the eye lens is 2.5 cm. What is the power of the eye lens when it is focused at its near point, 25 cm from the eye?

RRB Group-D 30/09/2022 / Shift-II 2022
✓ Answer: B 44 D
Using the lens formula with u = -0.25 m and v = 0.025 m: P = 1/f = 1/v - 1/u = 40 - (-4) = 44 D.