Q

An object of height 30 cm is placed in front of a concave lens and an image of height 10 cm is formed. What is the magnification?

RRB Technicians Grade-III 24/12/2024 / Shift-I 2024
✓ Answer: C 1/3
m = h'/h = 10/30 = +1/3. The image is erect. The negative sign used in the source explanation is incorrect.
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