Q

A constant force acts on an 8 kg object for 3 s, increasing its velocity from 4 m/s to 6 m/s. Find the force.

RRB Group D 27/09/2018 / Shift-I 2018
✓ Answer: A 5.33 N
F = 8(6 − 4)/3 = 16/3 ≈ 5.33 N.
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