Q

A 100 g cricket ball moving at 30 m/s is stopped by a player in 0.05 s. What is the average force exerted by the player?

RRB Group D 23/10/2018 / Shift-II 2018
✓ Answer: C −60 N
Taking the initial direction as positive, F = 0.1(0 − 30)/0.05 = −60 N.
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