Q

A 0.5 kg cube moves at 2.0 m/s on a smooth surface and collides with a stationary 1.0 kg object. They stick together. Find the energy lost.

RRB Group D 10/12/2018 / Shift-III 2018
✓ Answer: C 0.67 J
Their common speed is (0.5 × 2)/1.5 = 2/3 m/s. Energy lost = 1 − (1/2)(1.5)(2/3)² = 2/3 J ≈ 0.67 J.
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