If the molecular mass of an alkane is 44, then its molecular formula is:

For an alkane with a molecular mass of 44, the molecular formula is C3H8 (propane). Alkanes follow the general formula CnH2n+2. By substituting the atomic masses (C=12, H=1), the equation becomes 12n + 1(2n+2) = 44. Simplifying the equation gives 14n + 2 = 44, hence n = 3. For C3H8, the mass is (3x12) + (8x1) = 36 + 8 = 44.